LeetCode problem 3396,In this post, I’ll walk through my two solutions to LeetCode Problem 3396: Minimum Number of Operations to Make Elements in Array Distinct, using pythonic a ...

LeetCode 993: Cousins in Binary Tree – DFS and BFS Approaches Explained (Python), LeetCode 993: Cousins in Binary Tree – DFS and BFS Explained (Python) In this post, I’ll walk t...

Desafio do LeetCode: Validação de Sequência de Parênteses, Introdução Neste artigo, vou apresentar a implementação de um desafio simples de validação de caracteres de tex...

Invert Binary Tree in Java, Invert Binary Tree - A Step-by-Step Journey Binary trees are a fascinating data structure, and problems involving them often show up in coding interview...

Solving the Valid Palindrome Problem in Java, Hey there! If you’re prepping for coding interviews or just love a good string problem, you’ve probably come across the Valid Palind...

Best Time to Buy and Sell Stock in Java, Solving the Best Time to Buy and Sell Stock Problem in Java When it comes to algorithmic problem-solving, one of the classic challenges tha...

Java的栈与队列以及代码实现, Java栈和队列 栈的概念（Stack） 栈的实现 代码 队列（Queue） 模拟实现队列(双链表实现) 循环队列（循环数组实现） 用队列实现栈 用栈来实现队列 总结 栈的概念（...

LeetCode — 2807. Insert Greatest Common Divisors in Linked List,It’s a medium problem with the description being: Given the head of a linked list head, in which each node contain...

My LeetCode Experience, My LeetCode Experience: From Fibonacci to Dynamic Programming When I first started tackling LeetCode problems, even the basics like Fibonacci and Two Sum fe...

Why Python’s Sort Is Faster Than You Think , Timsort Timsort is a sorting algorithm that combines merge sort and insertion sort, and it has good efficiency in practice. Tim Peters...

Leetcode — 1486. XOR Operation in an Array,It’s an easy problem with description being: You are given an integer n and an integer start. Define an array nums where nums[i] = star...

Reorder List: LC 143 medium, GFG hard,Problem Link: Leetcode, Geeks for geeks Intuition We need to divide two pointers one at start and one at bottom Approach Step 1: first find th...